How can i remove an element or attribute from a json output while parsing from xml, using java
{"users": { "report": { "sub": "eng", "score": 30 }, "user": { "name": "test1", "age": 20 } }} my code is:
package project.example;
import org.json.JSONObject; import org.json.XML;
public class Xml2Json {
private static final int PRETTY_PRINT_INDENT_FACTOR = 4; public static void main(String[] args) { String xmlString = "<users><user name=test1 age=20></user><report sub=eng score=30></report></users>"; JSONObject jsonObject = XML.toJSONObject(xmlString); system.out.println(jsonObject);
this is the output i got when an xml is parsed to json using java. now i want to remove age=20 from this output.
Could anyone help me to solve this? Thanks in advance!
If you don’t want to use XSLT, this would work as well:
String xmlString = "<users><user name=test1 age=20></user><report sub=eng score=30></report></users>"; JSONObject jsonObject = XML.toJSONObject(xmlString); jsonObject.getJSONObject("users").getJSONObject("user").remove("age"); System.out.println(jsonObject); Reading your last comment. you had it almost right. Just the order was wrong. You’re traversing the JSON tree from the top.
Consider preprocessing the XML using XSLT, or post-processing the JSON similarly.
With XSLT 3.0 you can combine the structural transformation and XML-to-JSON conversion into a single operation.
For example (assuming that the structure of your XML is fixed, and only the values vary):
<xsl:transform version="3.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="json"/> <xsl:template match="/"> <xsl:sequence select=' map{"users": map { "report": map { "sub": string(/users/report/@sub), "score": string(/users/report/@score) }, "user": map { "name": string(/users/user/@name) } }}'/> </xsl:template> </xsl:transform> The advantage of this approach over use of a standard conversion utility like XML.toJSONObject is that you have total control over the JSON that is generated.
