Replace nth Substring With nth Strings of Lists
I have a string like so:
"initWithType:bundleIdentifier:uniqueIdentifier:" and two lists like so:
['long long', 'id', 'id'] ['arg1', 'arg2', 'arg3'] and want to end up with the string:
"initWithType:(long long)arg1 bundleIdentifier:(id)arg2 uniqueIdentifier:(id)arg3" As you may see, I effectively need to replace every nth semicolon with the nth string in each list (plus a little formatting with parentheses and a space).
I have been trying to use .format and the * unpacking operator but have had little success.
You can use a combination of string formatting with zip:
s1 = "initWithType:bundleIdentifier:uniqueIdentifier:" l2 = ['long long', 'id', 'id'] l3 = ['arg1', 'arg2', 'arg3'] print(" ".join("{}:({}){}".format(a, b, c) for a, b, c in zip(s1.split(":"), l2, l3))) Edit: you can also use f-strings with Python >= 3.6 as suggested by @flakes:
print(" ".join(f"{a}:({b}){c}" for a, b, c in zip(s1.split(":"), l2, l3))) this will print
initWithType:(long long)arg1 bundleIdentifier:(id)arg2 uniqueIdentifier:(id)arg3 
