Python not throwing errors or exceptions, websocket on_message
Why is python not throwing errors or exceptions when I pass too many arguments to f()? Obviously, f() is not executed because of the error. I am using VS-Code and python 3.8. (If you want to replicate, you have to install the websocket_client package)
import websocket import json connection = "wss://ws-feed.pro.coinbase.com" subscription = json.dumps({ "type": "subscribe", "channels": [ { "name": "level2", "product_ids": ["BTC-USD"] } ] }) def f(msg): print(msg) def ws_message(ws, message): f("hi",True) #<--should throw a too many arguments error/exception def ws_open(ws): ws.send(subscription) def ws_thread(*args): ws = websocket.WebSocketApp( connection, on_message=ws_message, on_open=ws_open) ws.run_forever() ws_thread() 
This is due to a failsafe mechanism implemented here. If you’d like to track your exceptions, you should set a proper level to the logger. For that, do:
import websocket websocket._logging._logger.level = -99 # This will enable all levels of logging # Rest of your code goes here That way, after running your code, you would see:
File "blablabla/.local/lib/python3.7/site-packages/websocket/_app.py", line 346, in _callback callback(self, *args) File "blablabla/test/test.py", line 22, in ws_message f("hi", True) #<--should throw a too many arguments error/exception Your code would still be running, but you would be able to catch exceptions
