Python, how to merge three dictionary in one filtering for key?
I have the following dictionaries:
personale_dip={'a': [550.0], 'b': [157.65]} personale_dip_costo={'a': [1.0], 'b': [150.0]} personale_result={'a': 550.0, 'b': 23648.64} Personale_result has been obtained with the following code:
personale_result={k : v[0] * personale_dip_costo[k][0] for k, v in personale_dip.items() if k in personale_dip_costo} I want to create a new variable, called final_value that, that for each key (matching them across dictionary) summarize all three dictionary giving me the following result:
final_value={'a': [550.0, 1.0, 550.0], 'b': [157.65, 150.0, 23648.64]} How should I do it? Any help would be much appreciated. Thanks in advance!
EDIT
I have tried the following code:
from collections import defaultdict personale_dip = {'a': [550.0], 'b': [157.65]} personale_dip_costo = {'a': [1.0], 'b': [150.0]} personale_result = {'a': 550.0, 'b': 23648.64} data = defaultdict(list) for d in [personale_dip, personale_dip_costo, personale_result]: for k, v in d.items(): if isinstance(v, list): data[k].extend(v) else: data[k].append(v) but the result is
defaultdict(<class 'list'>, {'a': [550.0, 1.0, 550.0], 'b': [157.65, 150.0, 23648.64]}) If I want to obtain only
{'a': [550.0, 1.0, 550.0], 'b': [157.65, 150.0, 23648.64]} How could I get it?
Well, you where on the right track. Personally I would simply merge them:
final_value = {} for key in personale_result: final_value[key] = (personale_dip[key][0], personale_dip_costo[key][0], personal_result[key]) With your input this will give you:
>>> final_result {'a': [550.0, 1.0, 550.0], 'b': [157.65, 150.0, 23647.5]} Now personale_dip and personale_dip_costo are of type {string, list}. Currently your personale_result will simply ignore other values in that list, as will final_result.
ANSWER 2.0
personale_dip={'a': [550.0], 'b': [157.65]} personale_dip_costo={'a': [1.0], 'b': [150.0]} personale_result={'a': 550.0, 'b': 23648.64} final_value = {} for dictionary in [personale_dip, personale_dip_costo, personale_result]: for k,v in dictionary.items(): # if the key is there, then # check whether it a list or a normal string # if list add it like [] + [] # if not then add it like [] + [v] if k in final_value: if isinstance(v, type([])): final_value[k] += v else: final_value[k] += [v] else: if isinstance(v, type([])): final_value[k] = v else: final_value[k] = [v] print(final_value) OUTPUT
>>> {'a': [550.0, 1.0, 550.0], 'b': [157.65, 150.0, 23648.64]} This is edited, and gives you what you want.
personale_dip = {'a': [550.0], 'b': [157.65]} personale_dip_costo = {'a': [1.0], 'b': [150.0]} personale_result = dict() for key_pd in personale_dip: if key_pd in personale_dip_costo.keys(): personale_result[key_pd] = [personale_dip[key_pd][0], personale_dip_costo[key_pd][0], personale_dip[key_pd][0]*personale_dip_costo[key_pd][0]] This code should work considering the list inside the dict contains only 1 element. This will work even if personale_dip has more elements or vice versa.
