Different JsonSerializerSettings for different values in list
I am using this setting to serialize a list of objects in dotnet core 2.2:
var settings = new JsonSerializerSettings() { DateFormatString = "MM/dd/yyyy h:mm tt" } The problem is I want it to serialize and deserialize DateTimes with "MM/dd/yyyy" if DateTimes time equals to 0 and I found no dynamic way to do it in the same list with both values (DateTimes with different times, 0 or not 0)
You can write your own json converter for for this.
public class DateTimeStringConverter : JsonConverter { // allowable DateTime formats - update as required List<string> DateFormats => new List<string> { "MM/dd/yyyy", "MM/dd/yyyy h:mm tt" }; public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer) { var dateStr = (string)reader.Value; DateTime date; foreach (string format in DateFormats) { if (DateTime.TryParseExact(dateStr, format, CultureInfo.InvariantCulture, DateTimeStyles.None, out date)) { return date; } } throw new JsonException($"{dateStr} as not a valid date string."); } public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer) { DateTime date = DateTime.Parse(value.ToString()); // Time value of DateTime.Today is always "00:00:00" if (date.TimeOfDay == DateTime.Today.TimeOfDay) { serializer.Serialize(writer, date.ToString("MM/dd/yyyy")); } else { serializer.Serialize(writer, date.ToString("MM/dd/yyyy h:mm tt")); } } public override bool CanConvert(Type objectType) { return objectType == typeof(DateTime); } } You could improve this by changing DateFormats to public List and pass through valid DateTime formats when initializing JsonSerializerSettings.
Then you can apply the settings like this:
var settings = new JsonSerializerSettings(); settings.DateParseHandling = DateParseHandling.None; settings.Converters.Add(new DateTimeStringConverter()); // deserialize var model = JsonConvert.DeserializeObject<YourClass>(json, settings); // serialize var serializedJson = JsonConvert.SerializeObject(model, settings); This was inspired by the answer to this question
