How do we convert scala "geojson.foreach(obj => println(Json.prettyPrint(Json.toJson(obj))))" into Java?

Question

How do we convert scala "geojson.foreach(obj => println(Json.prettyPrint(Json.toJson(obj))))" into Java?

geojson.foreach(obj => println(Json.prettyPrint(Json.toJson(obj)))) I tried to convert in java using foreach loop but getting error. kss.foreach((f) -> System.out.println(Json.prettyPrint(Json.toJson(o,f)))); Like: Cannot …

Stephenlesliemarlene Asked on July 15, 2020 in Java.

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Answer 1

BuddyPress is a plugin for WordPress that enables you to create a social network or community website. It has all the...

Answer 2

I value you getting some margin to help me with this task. Without you, no part of this would have...

Answer 3

Try to define a Cohesive class, until and unless the methods are written relevant to the class and it defines...

Answer 4

Try to add exportAllData: true, as an other option, hope it helps :)

Answer 5

DataSet can read an XML, infer schema and create a tabular representation that's easy to manipulate: DataSet ip1 = new...

Answer 6

I created a class and used Xml Linq : using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Xml; using...

Answer 7

XDocument first = XDocument.Load(args[0]); XDocument second = XDocument.Load(args[1]); var result = new XElement( "ipaddresses", first.Root.Elements("ip") .Zip(second.Root.Elements("ip"), (f, s) => {...

Answer 8

Following your code for the header row, you could achieve this by an <xsl:apply-templates select="/report/order_actions/order_action[order_id = current()/order_id]" /> As well...

Answer 9